Question Number: #Phy9457

If the error in the measurement of the momentum of a particle is (+100%). Then the error in the measurement of kinetic energy is

A.) 400%
B.) 200%
C.) 300%
D.) 100%

Answer is option : C


The error in momentum P is 100% therefore reading is 2P. Hence, new kinetic energy
Error in Kinetic energy = {(K'-K)/K} × 100.
On substituting the values we get error = 300%

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