Question Number: #Com1462

In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with centre B) is drawn. If the circle cuts AB and BC at P and Q respectively, then AP: QC is equal to 


Options:
A.) 1:1
B.) 3:2
C.) 4:1
D.) 3:8


Answer is option : D

Question Related Topics:
Quantitative Ability
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